Consider HA the intermediate form of diprotic acid_ Ka for this species is 10-4 and Kb is 10-8 Nonetheless_ the Ka and Kb reactions proceed to nearly the same extent when NaHA is dissolved in water: Explain_ (Select all that apply:) Each mole of H+ reacts with one mole of OH- from the Kb reaction= HA Hzo == HzA OH- The net result is that the Ka reaction is driven almost as far towards completion as the Kb reaction_ The Kb reaction, with much greater equilibrium constant than Kar releases Ht: HA- ==Ht + A2- Each mole of H+ reacts with one mole of OH- from the Ka reaction= HA Hz0 == HzA OH- The net result is that the Kb reaction is driven almost as far towards completion as the Ka reaction_ The Ka reaction, with much greater equilibrium constant than Kbr releases H+ HA- =H+ + A2-