Calculate a net energy that the proton-proton cycle yields.
[tex]
[tex][tex]\begin{aligned}
&{ }_1^1 \mathrm{H}+{ }_1^1 \mathrm{H} \rightarrow{ }_1^2 \mathrm{H}+e^{+}+\nu(0.42 \mathrm{MeV}) \\
&{ }_1^2 \mathrm{H}+{ }_1^1 \mathrm{H} \rightarrow{ }_2^3 \mathrm{He}+\gamma(5.49 \mathrm{MeV}) \\
&{ }_2^3 \mathrm{He}+{ }_2^3 \mathrm{He} \rightarrow{ }_2^4 \mathrm{He}+2{ }_1^1 \mathrm{H}(12.86 \mathrm{MeV})
\end{aligned}[/tex][/tex]
[/tex]