Answer:
234.61 mol
Explanation:
According to the Ideal Gas Law:
PV=nRT
P= 200 atm
V= 30.0 L
T= 300 K
R= 0.0821 [tex]\frac{(atm)(L)}{(mol)(K)}[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{(200atm)(30.0L)}{0.0821\frac{(atm)(L)}{(mol)(K)}(300K)}\\n=234.61 mol[/tex]