Answer :
For a 286 ml balloon with a pressure of 766 mmHg at 22.8 °C, number of moles of gas are in the balloon is 0.011 mol.
using ideal gas equation , we get :
P V = n RT
where,
Pressure, P = 766 mmHg = 1 atm
Volume V = 286 mL = 0.286 L
R = 0.082 L atm / mol K
Temperature T = 22.8 °C = 295.8 K
P V = n RT
n = P V / RT
n = (1 × 0.286) / ( 0.082 × 295.8)
n = 0.011 mol
Thus, For a 286 ml balloon with a pressure of 766 mmHg at 22.8 °C, number of moles of gas are in the balloon is 0.011 mol.
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