Answer :
The chemical in question has the following molecular formula of a compound and a molecular weight of 178 g/mol: C6H12O6 is the molecular formula, and CH2O is the empirical formula.
The empirical formula is CH2, while the molecular formula of the compound is C6H12O6. Consider 100 g of the substance as an illustration. As a result, we have 6.72 g of hydrogen, 40.00 g of carbon, and 53.28 g of oxygen. Moles of carbon are equal to 40.00 g at 1 mol and 12.01 g at 3.331 mol. A mole is equivalent to 6.72 g of hydrogen divided by one mole of hydrogen. A mole of oxygen weighs 53.28 g, whereas a mol of hydrogen weighs 16.00 g. The formula is 3.331:6.67:3.330=1.000:2.00:1 1:2:1 for moles of C, H, and O. CH2O is the empirical formula. Its empirical formula is the most straightforward formula for a compound. The true formula is an integral multiple of the empirical formula. If the empirical formula is CH2O, then the proper formula is (CH2O)n or CnH2nOn, where n = 1, 2, 3,... It is up to us to figure out what n is worth. The molecular mass of 180.18 u must be a multiple of CH2O's empirical formula mass of 30.03 u. n=180.18 u30.03 u = 6.000 ≈ 6 \s∴ In terms of chemistry, CnH2nOn = C6H12O6.
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