Answer :
The amount of CaCl₂ will be produced, if 5.00 g of Ca will react with 350 ml of 1.2 m HCl solution is 13.87 g.
The balanced equation is given as :
Ca + 2HCl ----> CaCl₂ + H₂
moles of Ca = mass / molar mass
= 5 / 40
= 0.125 mol
moles of HCl = molarity × volume
= 1.2 × 0.350
= 0.42 mol
1 mol of Ca react with 2 mol of HCl
0.045 mol of Ca = 2 × 0.125
= 0.25 mol HCl
therefore , Ca is the limiting reagent
1 mole Ca produced = 1 mole of CaCl₂
mole of CaCl₂ = 0.045 mol
mass of CaCl₂ = moles × molar mass
= 0.125 × 110.98
= 13.87 g
Thus, The amount of CaCl₂ will be produced, if 5.00 g of Ca will react with 350 ml of 1.2 m HCl solution is 13.87 g.
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