If 126 ml of a 1.1 m glucose solution is diluted to 450.0 ml , the molarity of the diluted solution is 0.30 M
given that :
molarity M1 = 1.1 M
volume V1 = 126 ml
volume V2 =450 ml
molarity M2 = ?
using the dilution law , we get ;
M1 V1 =M2 V2
M2 = (M1 V1) / V2
M2 = (1.1 × 126 ) / 450
M2 = 0.30 M
Thus, If 126 ml of a 1.1 m glucose solution is diluted to 450.0 ml , the molarity of the diluted solution is 0.30 M
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