Warming 1g of liquid water from 0°C to 100°C required more energy than vaporizing 1g of water to 100c.
Vaporizing 1g of water at 100°C explains the latent heat of vaporization .This is defined as the heat required to change one mole of liquid at the boiling point under standard atmospheric pressure .This is a physical properties of the substance. It takes 100 calories to heat 1 gram of water to 0° to 100° c. here o°c is the freezing point of water and 100c is the boiling point of water. the energy required to warm 1 g of water to 100c is 540 calories. Evaporation of water defines the conversion of water from the liquid to the gaseus state and it involves lots of energy.539 calories of enenrgy is required for the vaporization of water to 100c.
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