Answer :

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The right answer is option (e) i.e., Na₂CO₃ + H2₂SO₄ react with each other and form bubbles (gas) as a product .

Formation of Bubble (gas) :

Because both compounds are aqueous solution they dissociate into their elements.

carbonate ion in sodium carbonate will act as a Bronsted or Lowry base, accept the protons (H+) from the sulfuric acid to create carbon dioxide gas and water.

Na₂CO₃ + H2₂SO₄ --> Na₂SO₄ + CO₂ + H₂O

Sodium Carbonate + Sulfuric Acid -> Sodium Sulfate + Water + Carbon Dioxide

Mechanism :

  • Molecular equation

H₂SO₄ + Na₂CO₃ ===> Na₂SO₄ + CO₂ + H₂O

  • In ionic form of above equation

2H⁺ +SO₄²⁻+ 2Na⁺ + CO₃²⁻ ===> 2Na⁺ +SO₄²⁻ + CO₂ + H₂O

  • Net ionic equation and products which are formed

2H⁺ + CO₃²⁻ ===> CO₂ + H₂O

Neutralization is actually occurring when an OH⁻ from the base combines with an H⁺ from the acid to form H₂O and a salt and in this case Na₂SO₄ and CO₂ which is been liberated. So, we get formation of gas in Sodium Carbonate + Sulfuric Acid reaction .

To learn more about Bubble (gas) , refer:

https://brainly.com/question/2390639

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Complete Question:

Which reaction will produce bubbles (gas)?

Group of answer choices

a) NaOH + H₂SO₄

b) Na₂CO₃ + BaCl₂

c) BaCl₂ + H₂SO₄

d) NaOH + Na₂CO₃

e) Na₂CO₃ + H₂SO₄

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