Answer :
the empirical formula of this compound is found to be: C7H8
There is a specific small representative unit for each covalent or ionic chemical molecule that precisely describes its structure. Here, valence electron pairs from two or more distinct elements are shared to form bonds between atoms. The simplest way to express the make-up of this molecular unit is by the empirical formula of a compound.
The ratio of the number of atoms (in integers) in a compound is the empirical formula.
Suppose the given compound is 100 gram, then:
For C atoms:
moles of C= mass of C/ molar mass of C
mass of C = 81. 71% × 100 gram = 81.71 gram
molar mass of C= 12.01 g/mol
Hence,
moles of C = 81.71 / 12.01 = 6.8 mol
For H atoms:
moles of H = mass of H / molar mass of H
mass of H = 8.29% × 100 gram = 8.29 gram
molar mass of H = 1.008 g/mol
Hence,
moles of H = 8.29 / 1.008 = 8.22 mol
Thus the ratio of moles:
mol C:mol H =6.8: 8.22
mol C: mol H = 7: 8
Hence, the empirical formula is C7H8
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