Answer :
As 30.0 ml of 0.100 m sodium hypochlorite (NaOCl) solution to which he adds 55.0 ml of 0.0500 m HOCl. the pH of the resulting solution is 7.5.
The moles of HOCl is given as :
moles = 0.100 × 0.03 = 0.003 mol
The moles of NaOCl ios given as :
moles = 0.0500 × 0.055 = 0.0027 mol
Total volume = 30 mL + 55 mL = 85 mL = 0.085 L
the concentration of [HOCl] = 0.003 / 0.085 = 0.03 M
the concentration of [OCl⁻] = 0.0027 / 0.085 = 0.03 M
pka = -log ka
the pH formula is given as :
pH = pka + log [base] / [acid]
pH = 7.5 + log [ 0.03] / [0.03]
pH = 7.5
Thus, As 30.0 ml of 0.100 m sodium hypochlorite (NaOCl) solution to which he adds 55.0 ml of 0.0500 m HOCl. the pH of the resulting solution is 7.5.
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