Using Normal distribution,
the minimum required iq is 126.66 for admission into organization.
Normal Probability Problem:
In this problem, we are using the z-score of a normal distribution to calculate the minimum IQ value. The z-score is used to convert a random variable into a standard normal variate with mean zero and unit variance.
we have given that,
Normal Distribution: μ = 105 , σ = 15
Normal curve equation is
Z = (X- u)/sd ~ N( 1 ; 0)
P( Z> x ) = 0.04
the value of z to the cumulative probability 0.04 from normal table is 1.7544
P((X-u)/sd > x - 105/15 ) = 0.04
=> x - 105 / 15 = 1.7544
=> x = 1.7544 × 15 + 105 = 126.66
so, the minimum iq required for admission is 126.66..
To learn more about Normal distribution, refer:
https://brainly.com/question/23418254
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