Answer :
The mean of this distribution is 0.55
The standard error of this distribution is 0.0384
We have the following:
p=0.55
sample size, n=168
Mean of distribution:
Mean=true proportion of voters who support a restaurant
Mean=p=0.55
Hence, the mean of distribution is 0.55
Standard error of the distribution:
[tex]=\sqrt{\frac{p(1-p)}{n} }[/tex]
[tex]=\sqrt{\frac{0.55(1-0.55)}{168} }[/tex]
=0.0384
Hence, the standard error is 0.0384
Learn more about mean and standard error of distributions here:
https://brainly.com/question/14467769
#SPJ4
The questions was incomplete, the complete question is given below:
Suppose the true proportion of voters in the county who support a restaurant tax is 0.55. Consider the sampling distribution for the proportion of supporters with sample size n = 168.
What is the mean of this distribution?
What is the standard error of this distribution?
