Match the hyperbolas represented by the equations to their foci.
(a + 2)² _ (v-5)² = 1
82
(y + 5)²
6
-
-
(-1)²
82
=
1
= 1
(0-4)²
82
53
(1, -22) and (1, 12)
(-7, 5) and (3, 5)
-
(-7, -10) and (-7, 16)
-
(y + 2)²
15²
(-6, -2) and (14, -2)<
12²
= 1
=
= 1
=
(y + 5)²
152
-
(v − 3)² – (z +-7) ²
-
52
= 1
= 1