OABC is a parallelogram.
OA = a and OC = c
X is the midpoint of the line AC.
OCD is a straight line so that OC : OD = k : 1
XD = 4c - [tex]\frac{1}{2}[/tex] a

a) Find OX in terms of a and c, OX = (Answer here) (1)
b) CD = CX + (Answer here) (1)
c) Work out the value of k. k = (Answer here) (2)

Question

09-11-2022
Mathematics

Answered

OABC is a parallelogram.
OA = a and OC = c
X is the midpoint of the line AC.
OCD is a straight line so that OC : OD = k : 1
XD = 4c - [tex]\frac{1}{2}[/tex] a

a) Find OX in terms of a and c, OX = (Answer here) (1)
b) CD = CX + (Answer here) (1)
c) Work out the value of k. k = (Answer here) (2)

$OABC is a parallelogram OA a and OC c X is the midpoint of the line AC OCD is a straight line so that OC OD k 1 XD 4c texfrac12tex a a Find OX in terms of a and class=$

Answer :

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OABC is a parallelogram. OA = a and OC = c X is the midpoint of the line AC. OCD is a straight line so that OC : OD = k : 1 XD = 4c - [tex]\frac{1}{2}[/tex] a a) Find OX in terms of a and c, OX = (Answer here) (1) b) CD = CX + (Answer here) (1) c) Work out the value of k. k = (Answer here) (2)

Answer :

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OABC is a parallelogram.
OA = a and OC = c
X is the midpoint of the line AC.
OCD is a straight line so that OC : OD = k : 1
XD = 4c - [tex]\frac{1}{2}[/tex] a

a) Find OX in terms of a and c, OX = (Answer here) (1)
b) CD = CX + (Answer here) (1)
c) Work out the value of k. k = (Answer here) (2)