If 275 mL of 0.250 M BaCl₂ is added to 225 mL of 0.125 M Na₃PO₄, how many moles of Ba₃(PO₄)₂ precipitate will be formed? The balanced equation is

3 BaCl₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaCl(aq)