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An object with mass m is attached to the end of a string and is raised vertically at a constant acceleration of g 6. If it has been raised a distance l from rest, how much work has been done by the tension in the string?.



Answer :

11/10 MgL work has been done by the tension in the string.  If the object has been raised a distance l from rest.

Define work done?

The definition of work is expanded so that it encompasses both the forces applied to the body and the overall displacement of the body. A constant force F is present before this block. The objective of this force is to move the body d meters in a straight line in the force's direction.

Given,

Mass of object, M

Acceleration of object, a = g/10

Distance covered vertically, L

Tension of string, T

Work done by tension in string, W

W = T × L

By applying equilibrium force on string,

T - Mg = Ma

g = gravitational acceleration

T - Mg = M (g/10)

T = M(g/10) + Mg

T = 11/10 Mg

By substituting the value in, W = T × L

W = 11/10 Mg × L

W = 11/10 MgL

∴ Work done by tension is 11/10 MgL.

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