NaOH is a mono base, whereas HCl is a mono acid. Therefore, 1 mole of NaOH is required to neutralize 1 mole of HCl.
Here, we will determine how much H 2 S O 4 is necessary to neutralize 60.2 mL of a 0.427 M KOH solution. As a result, 0.01285 moles of H 2 S O 4 are required to neutralize the KOH in the provided quantity. The number of moles per litre is the molarity of a solution. In 500 ml, you have 0.75 moles. As a result, you have 0.75 moles per liter, or 1.5 moles per liter, or one pound. vwX30 = 0.015 mol 1000 in 30 mL of 0.5 M H2SO4 500 mL is equal to 0.500 L of diluted solution because 30 mL of 0.5 M.
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