what mass of sodium formate, nahco2, must be dissolved in 250.0 ml of 0.100 m formic acid (hco2h) to yield a buffer solution of ph 3.88?



Answer :

15.13g is the mass of sodium formate, nahco2, must be dissolved in 250.0 ml of 0.100 m formic acid (hco2h) to yield a buffer solution of ph. 3.88

What is Sodium formate?

The sodium salt of formic acid, HCOOH, is sodium formate, HCOONa. It typically appears as a fine, white powder. Since formic acid can be produced cheaply and in large quantities by carbonylating methanol and hydrolyzing the ensuing methyl formate, sodium formate is often made by neutralizing formic acid with sodium hydroxide. In the final phase of the production of pentaerythritol and in the crossing Cannizzaro reaction of formaldehyde with the aldol reaction result trimethylol acetaldehyde [3-hydroxy-2,2-bis(hydroxymethyl)propenal], sodium formate is also inevitably produced as a by-product.

pH = pKa + log [base/acid]

3.88 = 3.752 + log (x / 1)  {1 comes from the 1.00 M formic acid}

log x = 0.128

x = -0.89 M (molarity)

MV = g/molar mass

(0.89 mol/L) (0.250 L) = x / 68.0069 g/mol

x =  15.13 g

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