by titration, it is found that 12.7 ml of 0.185 m naoh(aq) is needed to neutralize 25.0 ml of hcl(aq). calculate the concentration of the hcl solution.



Answer :

The concentration of HCl is 0.093 M

What is titration?

Titration is a typical quantitative chemical analysis method used in laboratories to ascertain the concentration of an identified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A reagent, also known as a titrant or titrator, is created as a standard solution with a specified volume and concentration.

The concentration of the analyte is determined by the titrant's reaction with an analyte solution (also known as the titrand). Titration volume refers to the volume of titrant that interacted with the analyte.

Given,

Volume of NaOH = 12.7 ml

Concentration of NaOH( MNaOH) = 0.185 M

Volume of NaOH= 25.0 ml

HCl  +  NaOH   →     NaCl  + H2

In this chemical reaction the ratio between the number of moles of HCl and NaOH is 1:1 .

moles of HCl = moles of NaOH

MHCl * Volume of HCl = MNaOH × Volume of NaOH

MHCl =  (MNaOH ×volume of NaOH)/ volume of HCl

MHCl = (   0.185  * 12.​7)/ 25

MHCl         = 0.093 M

​Hence, the concentration of HCl is 0.093 M

To know more about titration calculations from the given link

https://brainly.com/question/24068939

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