The position of a 280-g object is given (in meters) by x = 5.0t³ - 8.0t² - 44t, where t is in seconds. Determine the net rate of work done on this object (a) at t = 2.0 s and (b) at t= 4.0 s. (c) What is the average net power input during the interval from t = 0 s to t = 2.0 s, and in the interval from t = 2.0 s to 4.0 s?