anastasiazakala anastasiazakala

06-11-2022
Physics

Answered

A 2.40 kg stone is sliding in the +x-direction on a horizontal, frictionless surface. It collides with a 4.00 kg stone at rest. After the collision the 2.40 kg stone is moving at 3.60 m/s at an angle of 30.0∘ measured from the +x-direction toward the +y-direction and the 4.00 kg stone is moving at an angle of 45.0∘ measured from the +x-direction toward the −y-direction.
A) What is the y-component of momentum of the 2.40 kg stone after the collision?
B) What must be the y-component of momentum of the 4.00 kg stone after the collision?
C) What is the speed of the 4.00 kg stone after the collision?
D) What is the x-component of the total momentum of the two stones after the collision?
E) What is the speed of the 2.40 kg stone before the collision?

Answer :

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