a 45.0-kg girl is standing on a 150.-kg plank. the plank, origi- nally at rest, is free to slide on a frozen lake, which is a flat, fric- tionless surface. the girl begins to walk along the plank at a constant velocity of 1.50 m/s to the right relative to the plank. (a) what is her velocity relative to the surface of the ice?



Answer :

The velocity relative to the surface of the ice is 1.15 m/s.

Velocity is the directional pace of an item in motion as an indication of its rate of exchange in the role as determined from a selected frame of reference and as measured by way of a selected standard of time.

calculation:-

Vgirl = 1.50 m/s +Vpi

      = 1.50 m/s - (mg/mp)Vgirl

So, the velocity of the girl relative to the ice is,

V-girl = 1.50 ms⁻¹/1 + mg/mp

         = 1.50 m/s/1 + 45.0 / 150 kg

      = 1.15 m/s

Average velocity is defined as the trade in position or displacement (∆x) divided by the time durations (∆t) wherein the displacement takes place. The common velocity can be effective or negative depending upon the sign of the displacement. The SI unit of average velocity is meters per second (m/s or ms-1).

Average velocity is calculated by means of dividing your displacement through the entire time; the average pace is calculated by way of dividing the overall distance you traveled by means of the total time.

Learn more about velocity here:-brainly.com/question/1844960

#SPJ4