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5. Two vans of BHCC students leave the campus at the same time, both headed along thesame route to New York for a service project. A professor is driving one of the vans at anaverage of 40 mph. A BHCC student is driving another van at an average of 61 mph. How longwill it take for the two vans to be 63 miles apart? (5 points)



Answer :

It is given that

Speed of first van=40mph

Speed of second van=61mph

Distance=63 miles

We know that

[tex]\text{Speed}=\frac{dis\tan ce}{\text{time}}[/tex]

[tex]\text{time}=\frac{dis\tan ce}{\text{speed}}\ldots\text{.}\mathrm{}(1)[/tex]

Substitute distance =63 miles and speed=40mph, we get the time taken by the professor

[tex]\text{time}=\frac{63}{40}h[/tex]

[tex]\text{time}=1.575h[/tex]

Multiply by 60 to convert this time into minutes, we get

[tex]\text{time}=1.575\times60\text{minutes}[/tex]

[tex]\text{time}=94.5\text{minutes}[/tex]

94.5 minutes taken by the professor.

Substitute distance =63 miles and speed=61mph in equation (1), we get the time taken by the student

[tex]\text{time}=\frac{63}{61}h[/tex]

[tex]\text{time}=1.0328h[/tex]

Multiply by 60 to convert this time into minutes, we get

[tex]\text{time}=1.0328\times60\text{ minutes}[/tex]

[tex]\text{time}=61.9\text{ minutes}[/tex]

61.9 minutes taken by the student.

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