We have the parabola equation in standard form:
[tex]y=ax^2+bx+c[/tex]and we need to convert it into a vertex form:
[tex]y=A(x-h)^2+k[/tex]In order to obtain it, we can note that
[tex]f(x)=x^2-10x+74[/tex]can be rewritten as
[tex]f(x)=(x-5)^2-25+74[/tex]this is because
[tex](x-5)^2=x^2-10x+25[/tex]From our last result, we have
[tex]f(x)=(x-5)^2+49[/tex]By comparing this result with the general vertex form, we can note that
[tex]\begin{gathered} A=1 \\ h=5 \\ k=49 \end{gathered}[/tex]Therefore, the equation in vertex form is given by:
[tex]f(x)=(x-5)^2+49[/tex]with vertex:
[tex](h,k)=(5,49)[/tex]