Money is invested at two rates of interest. One rate is 9% and the other is 3%. If there is $800 more invested at 9% than at 3%, find the amount invested at each rate if the total annual interest received is $660. Let x= amount invested at 9% and y= amount invested at 3%. Then the system that models the problem is
{x=y+8000.09x+0.03y=660. Solve the system by using the method of addition.