The ph after 25.0 ml of the naoh solution have been added is 1.222.
You are aware that the balanced chemical equation states that sodium hydroxide and hydrochloric acid balance each other out in a 1:1 mole ratio.
NaOH (l) + HCl (l) = NaCl (l) + H2O (l)
As a result, equal amounts of sodium hydroxide and hydrochloric acid must be used to completely neutralize a substance, producing a neutral solution with a pH of 7 at ambient temperature.
Although the molarities of your two solutions are equivalent, the hydrochloric acid solution has a volume of 100 mL divided by 25.0 mL, which equals four.
[tex][H3O+]=(75⋅0.100103).moles H3O+125⋅103.L=(75⋅0.100125)mol L−1This means that you havepH=−log(75⋅0.100125)=1.222−−−−−[/tex]
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