Answer :
5 g of acetic acid are present in 100 g of solution, or 5% acetic, implies.
5 g is the mass of acetic acid.
Acetic acid's molar mass is 60 g/mol.
Mass divided by molar mass yields acetic acid moles.
= 5 / 60
= 0.0833
Acetic acid's molarity is equal to moles per volume.
= 0.0833 / 30 x 10^-3
= 2.78 M
0.005 moles of NaOH are equal to 10 x 0.5 / 1000.
NaOH + CH3COOH —————————-> CH3COONa + Water
0.0833 0.005 0 - ———————-> initial
After reaction,
0.0783 0 0.005
pH is calculated as [CH3COONa/CH3COOH] log pKa.
pH = 4.74 + log (0.005 / 0.0783)
pH = 3.54
A buffer is a substance that can withstand a pH change when acidic or basic substances are added. Small additions of acid or base can be neutralized by it, keeping the pH of the solution largely constant. This is crucial for procedures and/or reactions that call for particular and stable pH ranges.
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