The number of grams of N2 that are produced when 125g of NH3 reacts as 4NH3+6NO--->5N2 +6H20 is 256.865 g
- According to the stoichiometry, 4 moles of NH3 react to form 5 moles of N2 or 1 mole of NH3 reacts to form (5/4) moles of N2
- Molecular weight of NH3 = 17.031 g/mol
- Number of moles corresponds to 125 g of NH3 = (125 g) / (17.031 g/mol) = 7.339 mol
- Since 1mole of NH3 reacts to form (5/4) moles of N2 ; 7.339 mol NH3 reacts to form (5/4) x (7.339) moles of N2 = 9.173 mole
- The weight corresponds to 9.173 mole of N2 = (9.173 mole) x MW of N2 = (9.173 mole) x 28 g/mol = 256.865 g
- The required weight is 256.865 g
To learn more about stoichiometry visit:
brainly.com/question/9743981
#SPJ4
