Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5).

Recall that the zeroes are (2, 0), (3, 0), and (5, 0).

The linear factors of the cubic are (x - 2)(x - 3)(x - 5)

To solve for the leading coefficient, use -5= a(0 - 2)(0 - 3)(0 - 5).

a=1/6

Write the function:
f(x) =
x² +
x^3 -
x - ​

Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate 0 5 Recall that the zeroes are 2 0 3 0 and 5 0 The linear class=