Answer :
The heat absorbed or released by a substance when its temperature changes depend on its heat capacity (Cp). The Cp of the water is 1 cal/g°C. The heat released can be found by the following equation:
[tex]Q=mCp\Delta T[/tex]Where,
Q is the heat released or absorbed
m is the mas oof water, 15.5g
Cp is the heat capacity of water, 1cal/g°C
dT is the change in temperature
[tex]\begin{gathered} \Delta T=T_2-T_1=-10.0\degree C-22.5\degree C \\ \Delta T=-32.5\degree C \end{gathered}[/tex]We replace the known values
[tex]Q=15.5g\times1\frac{cal}{g\degree C}\times(-32.5\degree C)[/tex][tex]\begin{gathered} Q=15.5g\times1\frac{cal}{g\degree C}\times(-32.5\degree C) \\ Q=-503.75cal \end{gathered}[/tex]In Joules the heat released will be:
[tex]Q=-503.75cal\times\frac{4.1868J}{1cal}=-2019J[/tex]the heat has a negative value, this is because the water released heat.
Answer:
The amount of heat released is 504 calories or 2019 joules
