An object is added to a graduated cylinder containing 12. 5 ml of water. If the volume of the object is 7. 6 ml, what is the new volume of the water?.

Question

25-10-2022
Chemistry

Answered

An object is added to a graduated cylinder containing 12. 5 ml of water. If the volume of the object is 7. 6 ml, what is the new volume of the water?.

Answer :

Other Questions

what would be the effect on the reaction rateif 10 ml of dmf were used for the reactioninstead of 5 ml?

the partition coefficient of a neutral nonpolar organic compound x is 22. what volume of organic solvent (in ml) is required to extract 99% of a 15 gram sample

A 20. 0-ml sample of 0. 25 m hno3 is titrated with 0. 15 m naoh. What is the ph of the solution after 30. 0 ml of naoh have been added to the acid?.

calculate the ph of a solution made by adding 170 ml of 1.30 m hcl to 350 ml of 1.80 m nh3 solution.

calculate the volume of oxygen, in ml , consumed in 1 hr by an average man who weighs 184 lbs and has a vo2max reading of 48.0 ml o2/kg body mass/min.

a 25.0 ml sample of 0.100 m hbr solution is titrated with 0.050 m naoh solution. what is the ph after 25.0 ml of the naoh solution have been added? a 25.0 ml sa

what is the concentration in molarity of a solution prepared by mixing 477 ml of 2.11 m potassium chloride and 498 ml of 1.28 m potassium chloride?

last year, a blinn student titrated a 25.00 ml solution of 0.0200 m oxalic acid with an aqueous solution of kmno4. if it took 41.86 ml of this solution to reach

suppose you are given solutions of 1.00 m acetic acid and 1.00 m sodium acetate and are asked to make 100.00 ml of buffer at ph 5.00 using only these two soluti

4. what is the volume of 75.1 grams of co2 at 45.2 degrees celsius and a pressure of 1.251 atmospheres?

rekharaypriti8910 rekharaypriti8910 · Answer 1 · 2022-10-28T08:05:18-04:00

Pour enough water into the graduated cylinder to cover the object and read the volume. The object is placed on the cylinder and the volume is read again.

The difference between the two volumes is the volume of the object. The mass of the displaced liquid can be expressed in terms of density and volume m = ρV. The weight of the displaced liquid is W = mg. where g is the acceleration due to gravity. Therefore, the weight of the displaced liquid can be expressed as W = ρVg. The idea here is that the increase in water volume in the cylinder is due to the metal volume. This means that we can calculate the volume of metal by looking at the volume occupied by water + metal in the cylinder and the volume occupied by water alone.

Learn more about volume here-

https://brainly.com/question/1578538

#SPJ4