if trial 3 gave a corrected volume of 21.1 ml h2 at stp, and the student calculated that 9.64x10-4 moles of h2 should be generated in the reaction, what is the molar gas volume for this trial?



Answer :

21.5 ml  is the molar volume of gas for this trial.

Volume=21.1 ml

moles=9.64x10^-4

no. of moles= given volume/22.4 L

V=n×22.4 L

V=9.64x10^-4×22.4×1000 ml

V=21.5 ml

The equation relates the volume and number of moles of a gas. V is for volume, n is for the number of moles, and V is for molar volume. A proportionality constant known as the molar volume describes the volume of one mole of any gas at a specific temperature and pressure.

It is helpful to establish a standard temperature and pressure that may be used as reference conditions when comparing various gases since the volume and, consequently, the density of a gas rely on those two factors. The definitions of standard temperature and pressure are 0°C and 1 atm, respectively. Standard temperature and pressure are referred to as STP together.

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