Answer :
The empirical formula and the m0lecular formula of the organic compound
is CH5O3 and C2H10O6
mass % of C = 12/44 × 7.455/9.119 × 100 = 22.2938
mass % of H = 2/18 × 3.053/9.119 × 100 = 3.716
mass % of O = 100 - [ 22.2938+ 3.716]
= 73.991
moles of C = 22.2938/12 = 1.33 = 1.33/1.33 = 1
moles of H = 6.6999/1 = 6.66/1.33 = 5
moles of O = 73.991 / 16 = 4.5 = 4.5/1.33 = 3
empirical formula = CH5O3
Molecular formula = (empirical formula)n
n = molar mass/ empirical mass = 88.11/65 = 2
Molecular formula = C2H10O6
The most straightforward whole number ratio of atoms in a compound is its empirical formula. The empirical formula of sulphur monoxide, abbreviated SO, and disulfur dioxide, abbreviated S2O2, are two straightforward examples of this idea. As a result, the empirical formula for sulphur monoxide and disulfur dioxide, two compounds made of sulphur and oxygen, is the same. Their molecular formulae, which represent how many atoms are present in each molecule of a chemical compound, are different.
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