1. Starting with a 0. 1525 m hcl stock solution, three standard solutions are prepared by sequentially diluting 5. 00 ml of each solution to 100. 0 ml. What is the concentration of each solution?.



Answer :

Each solution has a concentration of 7.625 x 103 m, 3.8125 x 104 m, and 1.90625 x 105 m, respectively.

Dilution is the process of lowering a sample's concentration by incorporating more solvent, according to its definition. The following is the dilution formula.

C₁V₁ = C₂V₂

where C1 is the sample's initial concentration.

V1 is the initial sample volume.

After dilution, the ultimate concentration is C2.

After dilution, the ultimate total volume is V2.

Calculate the concentration of the diluted solution by entering the numbers into the formula.

first common answer

C₁V₁ = C₂V₂

0. 1525 m(5.00 ml) = C₂(100.0 ml) (100.0 ml)

C₂ = 7.625 x 10⁻³ m

Second common solution

C₁V₁ = C₂V₂

7.625 x 10⁻³ m(5.00 ml) = C₂ (100.0 ml)

C₂ = 3.8125 x 10⁻⁴ m

Third accepted option

C₁V₁ = C₂V₂

3.8125 x 10⁻⁴ m(5.00 ml) = C₂(100.0 ml) (100.0 ml)

C₂ = 1.90625 x 10⁻⁵ m

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