a 6.000 g sample of a compound containing only carbon, oxygen and ruthenium was analyzed and found to contain 1.352 g of carbon and 1.796 g of oxygen. if the formula mass (molar mass) of the compound is approximately 639 g/mol, what is its chemical formula? write your answer as cxoyruz, where x, y, and z are whole numbers, but not subscripted.

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25-10-2022
Chemistry

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a 6.000 g sample of a compound containing only carbon, oxygen and ruthenium was analyzed and found to contain 1.352 g of carbon and 1.796 g of oxygen. if the formula mass (molar mass) of the compound is approximately 639 g/mol, what is its chemical formula? write your answer as cxoyruz, where x, y, and z are whole numbers, but not subscripted.

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qwlilly qwlilly · Answer 1 · 2022-11-08T08:04:41-05:00

The chemical formal of the given compound is C6O6Ru4 where, x is 6, y is 6 and z is 4.

Chemical formula is the formula that gives the relative idea of a compound with its mass. So, according to the question, the given compound contains carbon, oxygen and ruthenium. We need to find the number of moles of the given molecules in the compound.

As we know, to find the number of moles we need to divide given mass by molar mass of the molecule.

Therefore, the number of moles of carbon = 1.352/ 12 = 112.66/ 1000

which is equal to 0.112 moles.

The number of moles of oxygen = 1.796/ 16 = 112/1000, which is equal to 0.112 mole.

The mass of the given compound is 6.000g. Therefore, the mass of ruthenium is 6.000 - (1.352 + 1.796) = 2.852 g.

The number of moles of ruthenium = 2.852/ 101.07 = 0.028 moles.

Now, we put the number of moles of all the molecules of the compound in a ratio.

So, we get,

0.112: 0.112: 0.028 = 3: 3: 2

Therefore, the chemical formula is (C3O3Ru2) x2 = C6O6Ru4

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