a 5.000 g sample of a compound containing only potassium, rhenium and chlorine was analyzed and found to contain 0.530 g of potassium and 1.935 g of chlorine. if the formula mass (molar mass) of the compound is approximately 734 g/mol, what is its chemical formula? write your answer as kxreyclz, where x, y, and z are whole numbers, but not subscripted.



Answer :

The chemical formula based on mentioned information is K1Cl6Re1.

Firstly calculating the mass of Rhenium. Using law of conservation of mass for the calculation.

Total mass = sum of individual mass of chlorine, potassium and Rhenium

Mass of Rhenium = 5 - (0.530 + 1.935)

Mass of Rhenium = 2.535 grams

Now calculating the number of moles of each atom. Number of moles will be calculated by division and the formula is -

Number of moles = mass ÷ molar mass

Number of moles of Potassium = 0.5÷39

Number of moles of Potassium = 0.01

Number of moles of Chlorine = 1.935 ÷ 35

Number of moles of Chlorine = 0.06

Number of moles of Rhenium = 2.535 ÷ 186

Number of moles of Rhenium = 0.01

So, predicting the chemical formula -

K : Cl : Re = 0.01 : 0.06 : 0.01

Multiplying all the three ratio with 100

K : Cl : Re = 1 : 6 : 1

So, the chemical formula is K1Cl6Re1.

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