Answer :
Answer
The molarity (M) of the H3PO4 solution = 1.0 M
Explanation
Given:
Mass of H3PO4 = 49.0 grams
Volume of the solution = 500 mL = 500/1000 = 0.5 L
What to find:
The molarity (M) of the H3PO4 solution.
Step-by-step solution:
Step 1: Convert 49.0 grams H3PO4 to moles using the mole formula.
[tex]Mole=\frac{Mass}{Molar\text{ }mass}[/tex]The molar mass of H3PO4 = 97.994 g/mol
So,
[tex]Mole=\frac{49.0\text{ }g}{97.994\text{ }g\text{/}mol}=0.50\text{ }mol[/tex]Step 2: Calculate the molarity of the solution using the molarity formula.
[tex]Molarity=\frac{Mole}{Volume\text{ }in\text{ }L}[/tex]Putting mole = 0.50 mol and volume = 0.50L into the formula, we have;
[tex]Molarity=\frac{0.50mol}{0.50L}=1.0\text{ }M[/tex]The molarity (M) of the H3PO4 solution = 1.0 M
