Y=-x^2+12x-4Complete the square for - x^2+12x-4Use ax^2+bx+cA=-1, b=12, c=-4Then Consider the vertex form of a parabola A(x+d)^2+eFind the value of d using the formula d= b/2ad=12/2 times -1Then Cancel the common factor of 12 and 2d=2 x 6/2 x -1Then move the negative one from the denominator of 6/-1d=-1 x 6 or d=-6Find the value of E using the formulae=c-b^2/4aFind the vertex formSubstitute the values of C, b, and a into the formulae=-4-12^2/4 x -1Then simplify e-4+36Then add-4 +36e= 32Then substitute the values of a, D, and E into the vertex form-(x-6)^2+32Answer y= -(x-6)^2+32Can you tell me if this is correct for the vertex form? Was it what was it called