3) Michael was asked to explain his steps on
number 6.
-2g + 6 = 2g - 14
both sides
First, I would add 2g to both sides because there is
a 29 on the left and I need to move the variables
all to one side. That would make 6 = 2g-14. Next I
would subtract six from both sides to move all the
constants to one side which would result in 2g = -20.
I would then divide both sides by 2 to get rid of the
coefficient resulting in g = -10.
The teacher told Michael that he was almost
correct but he made one mistakes. What is
Michael's mistake?
2
4.) Solve.