Consider a 3-atom molecule a-b-a for which b has a total of only two valence electrons. If you assume that b is a group ii metal, what is the bond angle for a-b-a? please answer in degrees to the nearest whole number.



Answer :

Consider a 3-atom molecule a-b-a for which b has a total of only two valence electrons if you assume that b is a group ii metal, then the bond angle for a-b-a is 180 degree

Valence electron is the s and p electron in the outermost shell and electron present in the inner shell are core electron and according to the valence shell electron pair repulsion theory and we that bond angle that an atom has with its neighbor which also called dihedral angle a group II metal has two valence electron there it can form only single bond then b will not have any lone pair and the ones digit in the group number is the number of valence electron and 180 degree bond angle means the atom are connected in straight line called 180 degree bond

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