The molar mass of the acid is 65 g/mol.
We know that the term neutralization is applied to the reaction between an ad and a base that produces salt and water only. In this case, we have been told that a monoprotic weak acid required 22. 50 ml of 0. 510 m sodium hydroxide to titrate it.
Let us recall that by the principle of the stoichiometry of the chemical reactions, the reaction between sodium hydroxide and a monoprotic acid has to be one is to one and we have to bear this in mind.
Thus;
Number of moles of sodium hydroxide = 22. 50/1000 L * 0. 510 M
= 0.0115 moles
This implies that 0.0115 moles of the acid was required also.
Since;
Number of moles = mass/molar mass
Molar mass = mass/Number of moles
Molar mass = 0. 75 g /0.0115 moles
= 65 g/mol
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