Let o be the point of intersection of the diagonals of a quadrilateral abcd. prove that abcd could be a trapezoid (that is, it has one pair of opposite sides parallel) if aaod=aboc



Answer :

Given the details above, the sequence of steps below shows that ABCD is a Trapezoid.

What is a Trapezoid?

A trapezoid, also known as a trapezium, is a closed, flat object with four straight sides and one set of parallel sides. A trapezium's parallel sides are known as the bases, while its non-parallel sides are known as the legs.

Given:

The diagonals of the quadrilateral ABCD intersect at o where AO/BO = CO/DO; which also means that

AO/CO = BO/DO the proof is given as follows:

Create line OE || DC in a way that E lies on BC.

In ΔBDC, based on the Basic Proportionality Theory,

BO/OD = BE/EC ............................1

It is also given that:

AO/CO = BO/DO   ..........................2

Hence, from Equations 1 and 2,

AO/CO = BE/EC

Thus, we can state that on the basis of the Converse of the Basic Proportionality Theorem,

OE || AB

Since AB || OE || DC, it is correct to state that ABCD is a Trapezoid.

Learn more about Trapezoid:
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