uppose that a tcp segment has a lifetime of 2 minutes in the network. calculate the maximum transmission speed (bits/second) at which a host can send out 1460-byte tcp segments so that there will not be two tcp segments from the same sender with the same sequence number in the network, i.e., without having the tcp sequence numbers wrap around?

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pgld2554 pgld2554

21-10-2022
Computers and Technology

Answered

uppose that a tcp segment has a lifetime of 2 minutes in the network. calculate the maximum transmission speed (bits/second) at which a host can send out 1460-byte tcp segments so that there will not be two tcp segments from the same sender with the same sequence number in the network, i.e., without having the tcp sequence numbers wrap around?

Answer :

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tutorconsortium127 tutorconsortium127 · Answer 1 · 2022-10-27T05:01:49-04:00

The maximum transmission speed at which a host can send out 1460-bytes TCP segments from the same sender with the same sequence number in the network exists at 10 bits per second.

How to estimate the sustained maximum data transfer rate?

If the bandwidth exists at 10 Gbps, the link will be (10/8) 109 bps = 1.25 109 bps.

120 seconds is the maximum segment lifetime.

The amount of data transferred in 120 seconds exists equivalent to 150 1.25 109 bps / 120. 1.5 x 1010 bytes Equals 109 bytes

The TCP will generate a 1.5 1010 sequence number in the 120 seconds.

One is required to transfer data at the highest speed to make a 1.5 × 1010 unique sequence.

= ceiling(log(1.5 1010)

= ceil(log(1.5) + log(1010))

= ceil(0.1761 + 10)

= ceil(10.1761) (10.1761)

= 10 bits in the field for the sequence number.

Therefore, a sustained maximum data transfer rate of 10 bits per second exists required between two hosts.

To learn more about bytes refer to:

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