Suppose a projectile is fired from a cannon with velocity v0 and angle of elevation θ. The horizontal distance Rθ it travels (in feet) is given by the following. R(θ)=(v0)²sin2θ/32 If v0=80ft/s, what angle θ (in radians) should be used to hit a target on the ground 129 feet in front of the cannon? Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian. (If there is more than one answer, enter additional answers with the "or" button.)​