Calculate the pH for each of the cases in the titration of 25.0 mL of 0.200 M pyridine, C5H5N(aq) with 0.200 M HBr(aq). The b of pyridine is 1.7×10−9.
Before addition of any HBr
after addition of 12.5 mL of HBr
after addition of 18.0 mL of HBrHBr
after addition of 25.0 mL of HBr HBr
after addition of 30.0 mL of HBr HBr
Some explanation of the reasoning for the setup of the first two steps would be appreciated. Thank you.