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A particle moves along a straight line and its position at time t is given by s(t) = 2t³ - 18t² + 48t where
s is measured in feet and t in seconds.
Find the velocity (in ft/sec) of the particle at time t = 0: 48
The particle stops moving (i.e. is in a rest) twice,
first when t = 2
and again when t = 4
What is the position of the particle at time 12? 1440
Finally, what is the TOTAL distance the particle travels between time 0 and time 12?

A particle moves along a straight line and its position at time t is given by st 2t 18t 48t where s is measured in feet and t in seconds Find the velocity in ft class=


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