A brass plate has a 4.00 inch diameter hole in it. A rod with a diameter of 4.01 inches is to be
threaded through this plate to produce an interference fit. This is to be done by increasing the temperature of the plate, passing the rod through the plate, and then allowing the plate to return to its normal temperature. What must be the temperature change of the plate? (The coefficient of expansion per degree centigrade for brass is “19x10^-6 or 0.000019”)



Answer :