Plane A takes off at a 13° angle from the runway, and plane B takes off at a 9° angle from the runway. Which plane reaches a greater horizontal distance from the airport when the plane reaches an altitude of 10,000 feet? Round the solutions to the nearest whole number.


Plane A because it was 43,315 feet away


Plane A because it was 69,925 feet away


Plane B because it was 44,454 feet away


plane B because it was 63,138 feet away.



Okay so I figure out Sin degree for both the planes for plane A I got 44,545 and for plane B I got 63,925. I’m just so confused because the only answers I see are the numbers flip around, did I solve it wrong or something? I just don’t understand that the numbers are flip around, somebody please explain.