Answer:
160π
Step-by-step explanation:
The surface area of a right circular cylinder can be calculated using the following equation:
[tex]\boxed{\mathrm{Surface \ area = }2 \pi rh + 2 \pi r^2}[/tex] ,
where h is the height and r is the radius of the base of the cylinder.
We are told that the rod is 16 inches tall, therefore h = 16. We are also told that the radius of the base is 4 inches, therefore r = 4. Using this information along with the formula above, we can calculate the surface area of the metallic rod:
Surface area = [tex](2 \times \pi \times 4 \times 16) + (2 \times \pi \times (4)^2)[/tex]
= [tex]128\pi + 32\pi[/tex]
= [tex]\bf 160\pi[/tex]
Therefore the surface area of the metallic rod is 160π.
